2 rijen naast elkaar
ik wil de users van de website die online zijn
in tabellen en dan 2 rijen naast elkaar..
dit gebruik ik --->
Code (php)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
<?
if(isset($online)) {
$selectmembers = mysql_query("select * from lusers where user_active=1 ORDER BY user_id ASC LIMIT 12");
$countmembers= mysql_num_rows($selectmembers);
$profiledata = get_userdata($HTTP_GET_VARS["id"]);
function howManyYears($birthday) {
$today = time();
$remainder = $today - $birthday;
$age = floor($remainder / 31536000);
return $age;
}
if($countmembers > 0) {
while($listmembers = mysql_fetch_object($selectmembers)) {
echo "<table cellspacing=0 cellpadding=0 border=0 width=615><tr>
echo "<td height=60 width=60>";
echo "Username: <a href=profile.php?id=$listmembers->user_id><b>$listmembers->username</b></a>";
echo "</td>";
echo "</tr>";
}
}
echo "</table>";
}
?>
if(isset($online)) {
$selectmembers = mysql_query("select * from lusers where user_active=1 ORDER BY user_id ASC LIMIT 12");
$countmembers= mysql_num_rows($selectmembers);
$profiledata = get_userdata($HTTP_GET_VARS["id"]);
function howManyYears($birthday) {
$today = time();
$remainder = $today - $birthday;
$age = floor($remainder / 31536000);
return $age;
}
if($countmembers > 0) {
while($listmembers = mysql_fetch_object($selectmembers)) {
echo "<table cellspacing=0 cellpadding=0 border=0 width=615><tr>
echo "<td height=60 width=60>";
echo "Username: <a href=profile.php?id=$listmembers->user_id><b>$listmembers->username</b></a>";
echo "</td>";
echo "</tr>";
}
}
echo "</table>";
}
?>
ik weet wel wat ik moet gebruiken maar niet de plaats waar precies :S
Zoiets moet ik volges mij gebruiken:
en:
kan iemand mij helpen?!
Er zijn nog geen reacties op dit bericht.