count database
Warning: mysql_result(): supplied argument is not a valid MySQL result resource gastenboek_tekst.php on line 23
Gewijzigd op 01/01/1970 01:00:00 door Emile
Code (php)
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<?php
$query = "SELECT COUNT(id) AS aantal FROM gasten";
$res = mysql_query($query);
if($res){ // query gelukt!
$rtel = mysql_result($res,0);
}
else { // query mislukt
echo mysql_error();
echo $query;
}
?>
$query = "SELECT COUNT(id) AS aantal FROM gasten";
$res = mysql_query($query);
if($res){ // query gelukt!
$rtel = mysql_result($res,0);
}
else { // query mislukt
echo mysql_error();
echo $query;
}
?>