erigi in function check_referer($referers) werkt niet meer.
om de eregi functie te vervangen door de juiste functie.
Maar is volgens mij te hoog gegrepen voor me.
Mogelijk dat iemand kan helpen.
Code (php)
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function check_referer($referers)
{
// If there are any referrers in the list ...
if (count($referers))
{
$found = false;
// Use the browsers referrer header.
$temp = explode("/",getenv("HTTP_REFERER"));
$referer = $temp[2];
if ($referer=="")
{
$referer = $_SERVER['HTTP_REFERER'];
list($remove,$stuff)=split('//',$referer,2);
list($home,$stuff)=split('/',$stuff,2);
$referer = $home;
}
// Check agains list.
for ($x=0; $x < count($referers); $x++)
{
if (eregi ($referers[$x], $referer))
{
$found = true;
}
}
// Refererer is blank.
if ($referer =="")
$found = false;
if (!$found)
{
// You might alter this to print some sort of error of your own.
echo "<b>You are submitting entry from an <b>unauthorized domain.</b><br><br>";
}
return $found;
}
else
{
return true;
}
}
{
// If there are any referrers in the list ...
if (count($referers))
{
$found = false;
// Use the browsers referrer header.
$temp = explode("/",getenv("HTTP_REFERER"));
$referer = $temp[2];
if ($referer=="")
{
$referer = $_SERVER['HTTP_REFERER'];
list($remove,$stuff)=split('//',$referer,2);
list($home,$stuff)=split('/',$stuff,2);
$referer = $home;
}
// Check agains list.
for ($x=0; $x < count($referers); $x++)
{
if (eregi ($referers[$x], $referer))
{
$found = true;
}
}
// Refererer is blank.
if ($referer =="")
$found = false;
if (!$found)
{
// You might alter this to print some sort of error of your own.
echo "<b>You are submitting entry from an <b>unauthorized domain.</b><br><br>";
}
return $found;
}
else
{
return true;
}
}
Gewijzigd op 05/07/2015 18:54:04 door Willem L
Gewoon om de pattern een paar slashes als delimiter.
- enige historie? waar komt deze code vandaan, waar/waarvoor wordt deze gebruikt?
Dank je wel voor de genomen moeite. Kan wederom weer verder.
@Thomas
Dit komt vanuit Digioz gastenboek functions.php
// Function to detect if form submitted using injection ------------------------.