form met checkboxes uitlezen
Maar je weet toch zelf welke checkboxen er in het formulier staan.
Degene die je niet meekrijgt zijn dus niet aangevinkt.
bv zo:
Code (php)
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<?php
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
$alle_id = json_decode($_POST['ids']);
echo 'checkbox: ' . print_r($_POST['item'], 1) . '<br>';
echo "alle id's: " . print_r($alle_id, 1) . '<br>';
}
$ids = array(
15, 23, 41, 57, 98
);
$form = '';
foreach($ids as $id) {
$form .= '<input name="item[]" type="checkbox" value="' . $id . '">';
}
$form = '<form method="post">
' . $form . '
<input type="hidden" name="ids" value="' . json_encode($ids) . '">
<input type="submit" value="GO">
</form>';
echo $form;
?>
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
$alle_id = json_decode($_POST['ids']);
echo 'checkbox: ' . print_r($_POST['item'], 1) . '<br>';
echo "alle id's: " . print_r($alle_id, 1) . '<br>';
}
$ids = array(
15, 23, 41, 57, 98
);
$form = '';
foreach($ids as $id) {
$form .= '<input name="item[]" type="checkbox" value="' . $id . '">';
}
$form = '<form method="post">
' . $form . '
<input type="hidden" name="ids" value="' . json_encode($ids) . '">
<input type="submit" value="GO">
</form>';
echo $form;
?>
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Gewijzigd op 03/12/2013 10:50:22 door Ger van Steenderen
Code (php)
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echo "<input type='hidden' name='$comp_id' value='0' />";
echo "<input type='checkbox' name='$comp_id' value='1' />;
echo "<input type='checkbox' name='$comp_id' value='1' />;
Dank allen voor de hulp:-)