iemand enig idee wat hier fout aan is??
Warning: Supplied argument is not a valid MySQL result resource in c:\apache\htdocs\inbox.php on line 9
een gewone error maar snap dr nie veel van
Code (php)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
2
3
4
5
6
7
8
9
10
11
12
13
14
<?php
session_start();
include("style.css");
include("data.inc");
$global_dbh = mysql_connect($hostname, $username, $password);
mysql_select_db($db, $global_dbh);
$out = mysql_query(" SELECT * FROM berichten WHERE from = 'stef'");
while($row = mysql_fetch_assoc($out)){
echo "<p>" .$row['message']. "</p>";}
?>
session_start();
include("style.css");
include("data.inc");
$global_dbh = mysql_connect($hostname, $username, $password);
mysql_select_db($db, $global_dbh);
$out = mysql_query(" SELECT * FROM berichten WHERE from = 'stef'");
while($row = mysql_fetch_assoc($out)){
echo "<p>" .$row['message']. "</p>";}
?>
alvast bedankt
Code (php)
1
2
3
4
5
6
2
3
4
5
6
<?
$out = mysql_query("SELECT * FROM berichten WHERE from = 'stef'");
while($row = mysql_fetch_assoc($out)) {
echo "<p>" .$row['message']. "</p>";
}
?>
$out = mysql_query("SELECT * FROM berichten WHERE from = 'stef'");
while($row = mysql_fetch_assoc($out)) {
echo "<p>" .$row['message']. "</p>";
}
?>
denk ik.
Bienze:
Weet iemand misschien zo'n lijst te vinden met die 'speciale' verboden woorden??
Doe je best, op deze site staan ze allemaal.
Gewijzigd op 03/07/2005 15:23:00 door - SanThe -