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Mysql resultaten tabel > nieuwe regel
Ik zit met een tabel probleempje.
Ik wil mysql resultaten in een tabel zetten. Dit is gelukt, alleen komen alle resultaten horizontaal te staan, en ik wil dat er om de 4 resultaten een nieuwe regel gemaakt wordt.
Hier een screenshotje: http://collinkicken.nl/screen.jpg
Dit is het stukje php code dat er nu in zit:
Code (php)
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<?php
// Make a MySQL Connection
include "config.php"; //verbinding maken
$url1 = '<td height="130" bgcolor="#333333"><span class="box"><a href="film.php?id=';
$url2 = '">';
$url3 = '<img src="covers/';
$url4 = '.jpg" alt="" width="90" height="125" border="0" /></a></span></td>';
$url5 = '<td bgcolor="#333333" class="box2">';
$url6 = '</td>';
$url7 = '<td bgcolor="#333333" class="box2">';
$url8 = '</td>';
// Get all the data from the "example" table
$result = mysql_query("SELECT * FROM dvds ORDER BY titel ASC")
or die(mysql_error());
echo "<TABLE width=20% border=0> <TR> <TD width=25% height='130'>";
// keeps getting the next row until there are no more to get
while($row = mysql_fetch_array( $result )) {
// Print out the contents of each row into a table
echo "<TABLE width='100%' height='130'><TR>";
echo "<TD><table width='120' border='0' align='center'>";
echo "<tr>";
echo $url1;
echo $row['id'];
echo $url2;
echo $url3;
echo $row['id'];
echo $url4;
echo "</tr>";
echo "<tr>";
echo $url5;
echo $row['titel'];
echo $url6;
echo "</tr>";
echo "<tr>";
echo $url7;
echo $row['genre'];
echo $url8;
echo "</tr>";
echo "</table></TD>";
echo "</TR> </TABLE>";
echo "</TD> <TD>";
}
echo "</TD></TR></TABLE>";
?>
// Make a MySQL Connection
include "config.php"; //verbinding maken
$url1 = '<td height="130" bgcolor="#333333"><span class="box"><a href="film.php?id=';
$url2 = '">';
$url3 = '<img src="covers/';
$url4 = '.jpg" alt="" width="90" height="125" border="0" /></a></span></td>';
$url5 = '<td bgcolor="#333333" class="box2">';
$url6 = '</td>';
$url7 = '<td bgcolor="#333333" class="box2">';
$url8 = '</td>';
// Get all the data from the "example" table
$result = mysql_query("SELECT * FROM dvds ORDER BY titel ASC")
or die(mysql_error());
echo "<TABLE width=20% border=0> <TR> <TD width=25% height='130'>";
// keeps getting the next row until there are no more to get
while($row = mysql_fetch_array( $result )) {
// Print out the contents of each row into a table
echo "<TABLE width='100%' height='130'><TR>";
echo "<TD><table width='120' border='0' align='center'>";
echo "<tr>";
echo $url1;
echo $row['id'];
echo $url2;
echo $url3;
echo $row['id'];
echo $url4;
echo "</tr>";
echo "<tr>";
echo $url5;
echo $row['titel'];
echo $url6;
echo "</tr>";
echo "<tr>";
echo $url7;
echo $row['genre'];
echo $url8;
echo "</tr>";
echo "</table></TD>";
echo "</TR> </TABLE>";
echo "</TD> <TD>";
}
echo "</TD></TR></TABLE>";
?>
Ik denk dat ik moet tellen... maar hoe.
Alvast bedankt!
Code (php)
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if($x % 4 != 0){
echo '</tr><tr >';
}
echo '</tr><tr >';
}
Vergeet niet $x++ te doen in je while loop!
Gewijzigd op 01/01/1970 01:00:00 door Ee jee
Eejee schreef op 07.11.2008 09:10:
Vergeet niet $x++ te doen in je while loop!
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if($x % 4 != 0){
echo '</tr><tr >';
}
echo '</tr><tr >';
}
Vergeet niet $x++ te doen in je while loop!
Thnx!
Heb het nu zo:
// keeps getting the next row until there are no more to get
while($x++ $row = mysql_fetch_array( $result ))
if($x % 3 != 0){
echo '</tr><tr >';
}
{
// Print out the contents of each row into a table
Wil niet helemaal werken. Hoe klopt ie wel?
x vervangen voor row, ik denk dat t dan wel werkt....
Gewijzigd op 01/01/1970 01:00:00 door Tamara
Tamara schreef op 07.11.2008 09:22:
omdat $x misschien niet bestaat in jouw script?
x vervangen voor row, ik denk dat t dan wel werkt....
x vervangen voor row, ik denk dat t dan wel werkt....
Sorry wil nog niet helemaal werken.
Als ik het zo:
Code (php)
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<?php
// keeps getting the next row until there are no more to get
while($row = mysql_fetch_array( $result ).$row++)
if($x % 4 != 0){
echo '</tr><tr >';
}
{
?>
// keeps getting the next row until there are no more to get
while($row = mysql_fetch_array( $result ).$row++)
if($x % 4 != 0){
echo '</tr><tr >';
}
{
?>
// Print out the contents of each row into a table
Stopt de browser niet met laden en zie ik niets.
En zo:
Code (php)
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<?php
// keeps getting the next row until there are no more to get
while($row = mysql_fetch_array( $result ).$row++)
{
// Print out the contents of each row into a table
echo "<TABLE width='100%' height='130'><TR>";
echo "<TD><table width='120' border='0' align='center'>";
echo "<tr>";
echo $url1;
echo $row['id'];
echo $url2;
echo $url3;
echo $row['id'];
echo $url4;
echo "</tr>";
echo "<tr>";
echo $url5;
echo $row['titel'];
echo $url6;
echo "</tr>";
echo "<tr>";
echo $url7;
echo $row['genre'];
echo $url8;
echo "</tr>";
echo "</table></TD>";
echo "</TR> </TABLE>";
echo "</TD> <TD>";
}
echo "</TD></TR></TABLE>";
if($x % 4 != 0){
echo '</tr><tr >';
}
?>
// keeps getting the next row until there are no more to get
while($row = mysql_fetch_array( $result ).$row++)
{
// Print out the contents of each row into a table
echo "<TABLE width='100%' height='130'><TR>";
echo "<TD><table width='120' border='0' align='center'>";
echo "<tr>";
echo $url1;
echo $row['id'];
echo $url2;
echo $url3;
echo $row['id'];
echo $url4;
echo "</tr>";
echo "<tr>";
echo $url5;
echo $row['titel'];
echo $url6;
echo "</tr>";
echo "<tr>";
echo $url7;
echo $row['genre'];
echo $url8;
echo "</tr>";
echo "</table></TD>";
echo "</TR> </TABLE>";
echo "</TD> <TD>";
}
echo "</TD></TR></TABLE>";
if($x % 4 != 0){
echo '</tr><tr >';
}
?>
Zie ik dit: http://collinkicken.nl/screen2.jpg
Code (php)
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$x = 0;
while($row = mysql_fetch_array( $result ))
if($x % 3 != 0){
echo '</tr><tr >';
}
$x++;
{
while($row = mysql_fetch_array( $result ))
if($x % 3 != 0){
echo '</tr><tr >';
}
$x++;
{
Eejee schreef op 07.11.2008 09:40:
Code (php)
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$x = 0;
while($row = mysql_fetch_array( $result ))
if($x % 3 != 0){
echo '</tr><tr >';
}
$x++;
{
while($row = mysql_fetch_array( $result ))
if($x % 3 != 0){
echo '</tr><tr >';
}
$x++;
{
Thnx, maar dan wordt er maar 1 tabelletje geladen zonder inhoud.
in een for loop staat hij in het statement: for($x=0 .....), bij een while staat hij ervoor! $x=0; while(....)
jij geeft hier geen conditie mee en daarom zal je while niet uitgevoerd worden!
LEES:
FOR-LOOP
DO...WHILE/ WHILE
Dit moet werken(niet getest):
Code (php)
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<?php
// keeps getting the next row until there are no more to get
$x=0;
echo '<table border="0">
<tr>';
while($row = mysql_fetch_array( $result ))
{
// Print out the contents of each row into a table
echo '<td>';
echo $url1;
echo $row['id'];
echo $url2;
echo $url3;
echo $row['id'];
echo $url4;
echo "</tr>";
echo "<tr>";
echo $url5;
echo $row['titel'];
echo $url6;
echo "</tr>";
echo "<tr>";
echo $url7;
echo $row['genre'];
echo $url8;
echo '</td>';
if($x % 4 != 0){
echo '</tr><tr >';
}
$x++;
}
echo '</tr>
</table>';
?>
// keeps getting the next row until there are no more to get
$x=0;
echo '<table border="0">
<tr>';
while($row = mysql_fetch_array( $result ))
{
// Print out the contents of each row into a table
echo '<td>';
echo $url1;
echo $row['id'];
echo $url2;
echo $url3;
echo $row['id'];
echo $url4;
echo "</tr>";
echo "<tr>";
echo $url5;
echo $row['titel'];
echo $url6;
echo "</tr>";
echo "<tr>";
echo $url7;
echo $row['genre'];
echo $url8;
echo '</td>';
if($x % 4 != 0){
echo '</tr><tr >';
}
$x++;
}
echo '</tr>
</table>';
?>
uitleg:
Hij maakt een Tabel aan BUITEN de while(andersr krijg je bijv. 20 tabellen bij 20 plaatjes terwijl het niet hoeft)
ook de eerste Rij start je buiten de while..
Dan binnen de while maakt ie alleen <TD> INHOUD </TD> aan... na 4 <TD>'s(horizontale rijen dus) geeft ie </tr><tr> mee.. wat dus inhoud dat de eerste <tr> afgesloten wordt, en een nieuwe wordt gemaakt.
Zodra hij klaar is met loopen sluit hij de laatste </tr> buiten de while weer af.. een ook de tabel sluit ie dan af...
Gewijzigd op 01/01/1970 01:00:00 door Timen kut
Eejee schreef op 07.11.2008 10:21:
Alleen is je $x nog niet gedefinieerd. Of wil je de row gebruiken Timen?
vergeten :x aangepast ;)
Timen schreef op 07.11.2008 10:26:
vergeten :x aangepast ;)
Eejee schreef op 07.11.2008 10:21:
Alleen is je $x nog niet gedefinieerd. Of wil je de row gebruiken Timen?
vergeten :x aangepast ;)
Als ik het zo doe:
Code (php)
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<?php
// Make a MySQL Connection
include "config.php"; //verbinding maken
$url1 = '<td height="130" bgcolor="#333333"><span class="box"><a href="film.php?id=';
$url2 = '">';
$url3 = '<img src="covers/';
$url4 = '.jpg" alt="" width="90" height="125" border="0" /></a></span></td>';
$url5 = '<td bgcolor="#333333" class="box2">';
$url6 = '</td>';
$url7 = '<td bgcolor="#333333" class="box2">';
$url8 = '</td>';
// Get all the data from the "example" table
$result = mysql_query("SELECT * FROM dvds ORDER BY titel ASC")
or die(mysql_error());
echo "<TABLE width='583' border=0> <TR> <TD width=25% height='130'>";
// keeps getting the next row until there are no more to get
$x=0;
echo '<table border="0">
<tr>';
while($row = mysql_fetch_array( $result ).$row++)
{
// Print out the contents of each row into a table
echo '<td>';
echo $url1;
echo $row['id'];
echo $url2;
echo $url3;
echo $row['id'];
echo $url4;
echo "</tr>";
echo "<tr>";
echo $url5;
echo $row['titel'];
echo $url6;
echo "</tr>";
echo "<tr>";
echo $url7;
echo $row['genre'];
echo $url8;
echo '</td>';
if($x % 4 != 0){
echo '</tr><tr >';
}
$x++;
}
echo '</tr>
</table>';
?>
// Make a MySQL Connection
include "config.php"; //verbinding maken
$url1 = '<td height="130" bgcolor="#333333"><span class="box"><a href="film.php?id=';
$url2 = '">';
$url3 = '<img src="covers/';
$url4 = '.jpg" alt="" width="90" height="125" border="0" /></a></span></td>';
$url5 = '<td bgcolor="#333333" class="box2">';
$url6 = '</td>';
$url7 = '<td bgcolor="#333333" class="box2">';
$url8 = '</td>';
// Get all the data from the "example" table
$result = mysql_query("SELECT * FROM dvds ORDER BY titel ASC")
or die(mysql_error());
echo "<TABLE width='583' border=0> <TR> <TD width=25% height='130'>";
// keeps getting the next row until there are no more to get
$x=0;
echo '<table border="0">
<tr>';
while($row = mysql_fetch_array( $result ).$row++)
{
// Print out the contents of each row into a table
echo '<td>';
echo $url1;
echo $row['id'];
echo $url2;
echo $url3;
echo $row['id'];
echo $url4;
echo "</tr>";
echo "<tr>";
echo $url5;
echo $row['titel'];
echo $url6;
echo "</tr>";
echo "<tr>";
echo $url7;
echo $row['genre'];
echo $url8;
echo '</td>';
if($x % 4 != 0){
echo '</tr><tr >';
}
$x++;
}
echo '</tr>
</table>';
?>
Gebeurt er dit: http://collinkicken.nl/screen3.jpg
En zo:
Code (php)
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<?php
// Make a MySQL Connection
include "config.php"; //verbinding maken
$url1 = '<td height="130" bgcolor="#333333"><span class="box"><a href="film.php?id=';
$url2 = '">';
$url3 = '<img src="covers/';
$url4 = '.jpg" alt="" width="90" height="125" border="0" /></a></span></td>';
$url5 = '<td bgcolor="#333333" class="box2">';
$url6 = '</td>';
$url7 = '<td bgcolor="#333333" class="box2">';
$url8 = '</td>';
// Get all the data from the "example" table
$result = mysql_query("SELECT * FROM dvds ORDER BY titel ASC")
or die(mysql_error());
echo "<TABLE width='583' border=0> <TR> <TD width=25% height='130'>";
// keeps getting the next row until there are no more to get
$x=0;
while($row = mysql_fetch_array( $result ).$row++)
{
// Print out the contents of each row into a table
echo "<TABLE width='100%' height='130'><TR>";
echo "<TD><table width='120' border='0' align='center'>";
echo "<tr>";
echo $url1;
echo $row['id'];
echo $url2;
echo $url3;
echo $row['id'];
echo $url4;
echo "</tr>";
echo "<tr>";
echo $url5;
echo $row['titel'];
echo $url6;
echo "</tr>";
echo "<tr>";
echo $url7;
echo $row['genre'];
echo $url8;
echo "</tr>";
echo "</table></TD>";
echo "</TR> </TABLE>";
echo "</TD> <TD>";
if($x % 4 != 0){
echo '</tr><tr >';
}
$x++;
}
echo "</TD></TR></TABLE>";
?>
// Make a MySQL Connection
include "config.php"; //verbinding maken
$url1 = '<td height="130" bgcolor="#333333"><span class="box"><a href="film.php?id=';
$url2 = '">';
$url3 = '<img src="covers/';
$url4 = '.jpg" alt="" width="90" height="125" border="0" /></a></span></td>';
$url5 = '<td bgcolor="#333333" class="box2">';
$url6 = '</td>';
$url7 = '<td bgcolor="#333333" class="box2">';
$url8 = '</td>';
// Get all the data from the "example" table
$result = mysql_query("SELECT * FROM dvds ORDER BY titel ASC")
or die(mysql_error());
echo "<TABLE width='583' border=0> <TR> <TD width=25% height='130'>";
// keeps getting the next row until there are no more to get
$x=0;
while($row = mysql_fetch_array( $result ).$row++)
{
// Print out the contents of each row into a table
echo "<TABLE width='100%' height='130'><TR>";
echo "<TD><table width='120' border='0' align='center'>";
echo "<tr>";
echo $url1;
echo $row['id'];
echo $url2;
echo $url3;
echo $row['id'];
echo $url4;
echo "</tr>";
echo "<tr>";
echo $url5;
echo $row['titel'];
echo $url6;
echo "</tr>";
echo "<tr>";
echo $url7;
echo $row['genre'];
echo $url8;
echo "</tr>";
echo "</table></TD>";
echo "</TR> </TABLE>";
echo "</TD> <TD>";
if($x % 4 != 0){
echo '</tr><tr >';
}
$x++;
}
echo "</TD></TR></TABLE>";
?>
Gebeurt dit: http://collinkicken.nl/screen4.jpg
Volgensmij zitten we in de buurt :p
verder zou die code van mij moeten werken...
daarbij zie ik dat je IN je while nog steeds <tr> gebruikt, daardoor komt er natuurlijk weer een nieuwe rij te staan...
Een versimpelde versie van wat jij nodig hebt:
Code (php)
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$x=0;
echo "<TABLE width='583' border=0> <TR> <TD width=25% height='130'>
<tr>";
while($x<8)
{
// Print out the contents of each row into a table
echo '<td>';
echo $url1;
echo $row['id'];
echo $url2;
echo $url3;
echo $row['id'];
echo $url4;
echo '</td>';
if($x == 3){
echo '</tr><tr >';
}
$x++;
}
echo '</tr>
</table>';
}
echo '</tr>
</table>';
echo "<TABLE width='583' border=0> <TR> <TD width=25% height='130'>
<tr>";
while($x<8)
{
// Print out the contents of each row into a table
echo '<td>';
echo $url1;
echo $row['id'];
echo $url2;
echo $url3;
echo $row['id'];
echo $url4;
echo '</td>';
if($x == 3){
echo '</tr><tr >';
}
$x++;
}
echo '</tr>
</table>';
}
echo '</tr>
</table>';
resulteert in:
http://www.envyum.nl/resultaat.jpg
Je wil dus dat alleen één zo'n blokje in je while komt te staan... dus GEEN <TR>'s etc..
doordat de while hem looped krijg je dus automatisch iedere keer 1 zo'n blokje per resultaat uit je Database
Met dit als uitgangs punt moet je een heel eind kunnen komen(Dus niet letterlijk copy/paste want mijne gebruik geen query.
Gewijzigd op 01/01/1970 01:00:00 door Timen kut
Timen schreef op 07.11.2008 10:42:
Was zelf vergeten die .row++ uit mn while te halen, die er dus effe uithalen
verder zou die code van mij moeten werken...
verder zou die code van mij moeten werken...
Ok heb ik nu gedaan, dan gebeurt er dit: http://collinkicken.nl/screen5.jpg
Er gebeurt al wel een stuk meer xD thnx!
Collin schreef op 07.11.2008 10:49:
Ok heb ik nu gedaan, dan gebeurt er dit: http://collinkicken.nl/screen5.jpg
Er gebeurt al wel een stuk meer xD thnx!
Timen schreef op 07.11.2008 10:42:
Was zelf vergeten die .row++ uit mn while te halen, die er dus effe uithalen
verder zou die code van mij moeten werken...
verder zou die code van mij moeten werken...
Ok heb ik nu gedaan, dan gebeurt er dit: http://collinkicken.nl/screen5.jpg
Er gebeurt al wel een stuk meer xD thnx!
Lees mijn edit :)
Timen schreef op 07.11.2008 10:54:
Lees mijn edit :)
Collin schreef op 07.11.2008 10:49:
Ok heb ik nu gedaan, dan gebeurt er dit: http://collinkicken.nl/screen5.jpg
Er gebeurt al wel een stuk meer xD thnx!
Timen schreef op 07.11.2008 10:42:
Was zelf vergeten die .row++ uit mn while te halen, die er dus effe uithalen
verder zou die code van mij moeten werken...
verder zou die code van mij moeten werken...
Ok heb ik nu gedaan, dan gebeurt er dit: http://collinkicken.nl/screen5.jpg
Er gebeurt al wel een stuk meer xD thnx!
Lees mijn edit :)
Hehe sorry zag ik niet, ik ga even stoeien!
Eejee schreef op 07.11.2008 11:36:
Is het nou gelukt?
Nou, niet echt.
Ik krijg nu dit: http://collinkicken.nl/screen6.jpg
Met:
Code (php)
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<?php
// Make a MySQL Connection
include "config.php"; //verbinding maken
$url1 = '<td height="130" bgcolor="#333333"><span class="box"><a href="film.php?id=';
$url2 = '">';
$url3 = '<img src="covers/';
$url4 = '.jpg" alt="" width="90" height="125" border="0" /></a></span></td>';
$url5 = '<td bgcolor="#333333" class="box2">';
$url6 = '</td>';
$url7 = '<td bgcolor="#333333" class="box2">';
$url8 = '</td>';
// Get all the data from the "example" table
$result = mysql_query("SELECT * FROM dvds ORDER BY titel ASC")
or die(mysql_error());
$x=0;
echo "<TABLE width='583' border=0> <TR> <TD width=25% height='130'><tr>";
// keeps getting the next row until there are no more to get
while($row = mysql_fetch_array( $result ).$x<8)
{
// Print out the contents of each row into a table
echo "<TABLE width='100%' height='130'><TR>";
echo "<TD><table width='120' border='0' align='center'>";
echo $url1;
echo $row['id'];
echo $url2;
echo $url3;
echo $row['id'];
echo $url4;
echo $url5;
echo $row['titel'];
echo $url6;
echo $url7;
echo $row['genre'];
echo $url8;
echo "</table></TD>";
echo "</TR> </TABLE>";
echo "</TD> <TD>";
if($x == 3){
echo '</tr><tr >';
}
$x++;
}
echo "</TD></TR></TABLE>";
?>
// Make a MySQL Connection
include "config.php"; //verbinding maken
$url1 = '<td height="130" bgcolor="#333333"><span class="box"><a href="film.php?id=';
$url2 = '">';
$url3 = '<img src="covers/';
$url4 = '.jpg" alt="" width="90" height="125" border="0" /></a></span></td>';
$url5 = '<td bgcolor="#333333" class="box2">';
$url6 = '</td>';
$url7 = '<td bgcolor="#333333" class="box2">';
$url8 = '</td>';
// Get all the data from the "example" table
$result = mysql_query("SELECT * FROM dvds ORDER BY titel ASC")
or die(mysql_error());
$x=0;
echo "<TABLE width='583' border=0> <TR> <TD width=25% height='130'><tr>";
// keeps getting the next row until there are no more to get
while($row = mysql_fetch_array( $result ).$x<8)
{
// Print out the contents of each row into a table
echo "<TABLE width='100%' height='130'><TR>";
echo "<TD><table width='120' border='0' align='center'>";
echo $url1;
echo $row['id'];
echo $url2;
echo $url3;
echo $row['id'];
echo $url4;
echo $url5;
echo $row['titel'];
echo $url6;
echo $url7;
echo $row['genre'];
echo $url8;
echo "</table></TD>";
echo "</TR> </TABLE>";
echo "</TD> <TD>";
if($x == 3){
echo '</tr><tr >';
}
$x++;
}
echo "</TD></TR></TABLE>";
?>