Oneven regels andere kleur in tabel
Code (php)
De 1e regel van de tabel krijgt handmatig de kleur #CCFFCC mee. Nu wil ik elke oneven regel ook deze kleur geven. Hoe doe ik dit?
Nee hoor, grapje:
Code (php)
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<?php
echo "<table border=\"1\">\n";
echo "<tr bgcolor=\"#CCFFCC\"><td>Fruit</td></tr>\n";
$fruit = array(appel, peer, banaan, kiwi, sinsaasappel, perzik, mandarijn);
$fruit_num = count($fruit);
$flip = 0;
for ($i=0; $i<=$fruit_num; $i++){
$flip ^= 1;
echo "<tr class=\"bg" . $flip . "\"><td>$fruit[$i]</td></tr>\n";
}
echo "</table>";
?>
echo "<table border=\"1\">\n";
echo "<tr bgcolor=\"#CCFFCC\"><td>Fruit</td></tr>\n";
$fruit = array(appel, peer, banaan, kiwi, sinsaasappel, perzik, mandarijn);
$fruit_num = count($fruit);
$flip = 0;
for ($i=0; $i<=$fruit_num; $i++){
$flip ^= 1;
echo "<tr class=\"bg" . $flip . "\"><td>$fruit[$i]</td></tr>\n";
}
echo "</table>";
?>
In je CSS:
.bg0 {
background: #eee;
}
.bg1 {
background: #fff;
}
Online voorbeeld: alternating rows
Gewijzigd op 01/01/1970 01:00:00 door Jan Koehoorn
<table>
Code (php)
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</table>
Nu kan je om en om wat anders tonen.
Groet Cees
Cees schreef op 21.04.2007 20:39:
Ik zou het wat anders doen, het is niet nodig om standaard HTML door PHP te laten doen.
Da's een mooi stukje code Cees. Wat doet het precies?
%2 betekent modulus 2, dit betekent zoveel als, deel telkens door 2 en geef de restwaarde als er niet meer door 2 gedeeld kan worden terug.
Vanuit een database genereer ik een html-tabel. Ook daarvan zou ik de regels om en om een andere kleur willen geven...
Code (php)
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<?php
$dateset = mysql_query("SELECT DISTINCT Date FROM weerdata ORDER BY Date ASC", $db);
if ($dateset){
while ($date_result = mysql_fetch_array($dateset)){
if ($date_result[0] >= "2007-04-01" AND $date_result[0] <= "2007-04-31"){
echo "<tr><td>" . $date_result[0] . "</td>";
display_table_day($date_result[0]);
}
}
}
else {
echo "$error";
}
?>
$dateset = mysql_query("SELECT DISTINCT Date FROM weerdata ORDER BY Date ASC", $db);
if ($dateset){
while ($date_result = mysql_fetch_array($dateset)){
if ($date_result[0] >= "2007-04-01" AND $date_result[0] <= "2007-04-31"){
echo "<tr><td>" . $date_result[0] . "</td>";
display_table_day($date_result[0]);
}
}
}
else {
echo "$error";
}
?>
Rene schreef op 21.04.2007 21:39:
Bij mij werkt de code van Cees niet. Wat doet (count(fruit)%2) ?
Je moet ook die van mij gebruiken ;-)
Code (php)
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<?php
$dateset = mysql_query("SELECT DISTINCT Date FROM weerdata ORDER BY Date ASC", $db);
if ($dateset){
$flip = 0;
while ($date_result = mysql_fetch_array($dateset)){
if ($date_result[0] >= "2007-04-01" AND $date_result[0] <= "2007-04-31"){
$flip ^= 1;
echo "<tr class=\"bg".$flip."\"><td>" . $date_result[0] . "</td>";
display_table_day($date_result[0]);
}
}
}
else {
echo "$error";
}
?>
$dateset = mysql_query("SELECT DISTINCT Date FROM weerdata ORDER BY Date ASC", $db);
if ($dateset){
$flip = 0;
while ($date_result = mysql_fetch_array($dateset)){
if ($date_result[0] >= "2007-04-01" AND $date_result[0] <= "2007-04-31"){
$flip ^= 1;
echo "<tr class=\"bg".$flip."\"><td>" . $date_result[0] . "</td>";
display_table_day($date_result[0]);
}
}
}
else {
echo "$error";
}
?>
Dan worden ze allemaal dezelfde kleur...
Code (php)
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<?
$result=mysql_query("select * from products");
while($row=mysql_fetch_array($result)){
$flip = 0;
$flip ^= 1;
?>
<tr class=\"bg".$flip."\"></tr>
<td width="10%"><?=$row['picture']?></td>
<td width="20%"><?=$row['name']?></td>
<td width="20%"><?=$row['description']?></td>
<td width="20%"><?=$row['price']?></td>
<td width="20%"><input type="button" value="Add to Cart" onclick="addtocart(<?=$row['serial']?>)" /></td>
</tr>
<? } ?>
$result=mysql_query("select * from products");
while($row=mysql_fetch_array($result)){
$flip = 0;
$flip ^= 1;
?>
<tr class=\"bg".$flip."\"></tr>
<td width="10%"><?=$row['picture']?></td>
<td width="20%"><?=$row['name']?></td>
<td width="20%"><?=$row['description']?></td>
<td width="20%"><?=$row['price']?></td>
<td width="20%"><input type="button" value="Add to Cart" onclick="addtocart(<?=$row['serial']?>)" /></td>
</tr>
<? } ?>
Hopelijk kan iemand mij vertellen wat ik fout doe?
Je moet $flip = 0; natuurlijk wel vóór de while() zetten.
Gewijzigd op 01/03/2011 13:21:53 door - SanThe -
Code (php)
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<?php
...
for($i=0; $row=mysql_fetch_array($result); $i++){
$class = ($i%2==0 ? 'green' : 'blue' );
...
}
?>
...
for($i=0; $row=mysql_fetch_array($result); $i++){
$class = ($i%2==0 ? 'green' : 'blue' );
...
}
?>
Gewijzigd op 01/03/2011 13:31:11 door Kris Peeters
Code (php)
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<?
$result=mysql_query("select * from products");
for($i=0; $row=mysql_fetch_array($result); $i++){
$kleur="#fff";
if ($i &1){ $kleur = "#e7e6e2"; }
?>
<tr bgcolor=<?php echo $kleur; ?>>
<td width="10%"><?=$row['picture']?></td>
<td width="20%"><?=$row['name']?></td>
<td width="20%"><?=$row['description']?></td>
<td width="20%"><?=$row['price']?></td>
<td width="20%"><?=$row['price']?></td>
<td width="20%"><input type="button" value="Add to Cart" onclick="addtocart(<?=$row['serial']?>)" /></td>
</tr>
<? } ?>
$result=mysql_query("select * from products");
for($i=0; $row=mysql_fetch_array($result); $i++){
$kleur="#fff";
if ($i &1){ $kleur = "#e7e6e2"; }
?>
<tr bgcolor=<?php echo $kleur; ?>>
<td width="10%"><?=$row['picture']?></td>
<td width="20%"><?=$row['name']?></td>
<td width="20%"><?=$row['description']?></td>
<td width="20%"><?=$row['price']?></td>
<td width="20%"><?=$row['price']?></td>
<td width="20%"><input type="button" value="Add to Cart" onclick="addtocart(<?=$row['serial']?>)" /></td>
</tr>
<? } ?>
Hartelijk dank
Code (php)
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<?=$row['name']?>
En ook geen
Code (php)
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<? ?>
Code (php)
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<?php ?>
En je code is helemaal af/