variable met cijfer er achter
De tabel bestaat uit twee velden; id en uitleg.
Met de query probeer ik het volgende te bereiken, waarbij blabla de uitleg is:
$u1 = "blabla"
$u2 = "blabla"
$u3 = "blabla"
etc
De query waarmee ik dat probeer is:
Code (php)
1
2
3
4
5
6
7
8
9
10
11
12
2
3
4
5
6
7
8
9
10
11
12
<?php
include('../dbconnect.php');
$select = mysql_query("SELECT id,uitleg FROM uitlegbaby ORDER BY id") or die(mysql_error());
while($row = mysql_fetch_array($select)) {
$id = $row['id'];
$uitleg = $row['uitleg'];
if ($id == $id) { $u."$id" = $uitleg }
}
?>
include('../dbconnect.php');
$select = mysql_query("SELECT id,uitleg FROM uitlegbaby ORDER BY id") or die(mysql_error());
while($row = mysql_fetch_array($select)) {
$id = $row['id'];
$uitleg = $row['uitleg'];
if ($id == $id) { $u."$id" = $uitleg }
}
?>
Wat doe ik fout, buiten de "or die"?
Code (php)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
2
3
4
5
6
7
8
9
10
11
12
13
14
<?php
include('../dbconnect.php');
$u = array();
$select = mysql_query("SELECT id,uitleg FROM uitlegbaby ORDER BY id") or die(mysql_error());
while($row = mysql_fetch_array($select)) {
$id = $row['id'];
$uitleg = $row['uitleg'];
$u[$id] = $uitleg;
}
?>
include('../dbconnect.php');
$u = array();
$select = mysql_query("SELECT id,uitleg FROM uitlegbaby ORDER BY id") or die(mysql_error());
while($row = mysql_fetch_array($select)) {
$id = $row['id'];
$uitleg = $row['uitleg'];
$u[$id] = $uitleg;
}
?>