variable word niet weergegeven.
In mijn script word de variable $list->userid niet weergegeven die in het select listje staan.
Heeft iemand meschien eenig idee hoe ik doot kan oplossen?
Code (php)
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<?php
$sql = "SELECT * FROM unitmembers WHERE unitid = 10";
$res = mysql_query($sql) or die (mysql_error());
while($list = mysql_fetch_object($res)) {
<script language="javascript">
function addDropDown(aantal) {
document.getElementById('naar').innerHTML = '';
for (i = 1; i <= aantal; i++ ) {
document.getElementById('naar').innerHTML += 'Player:<select name="text"><option value="$list->userid">$list->userid</option></select><br><br>';
}
}
</script>
}
echo'<select name="van" onChange="addDropDown(this.value);">';
echo'<option>- Losing Players -</option>';
echo'<option value="2">2</option>';
echo'<option value="3">3</option>';
echo'<option value="4">4</option>';
echo'<option value="5">5</option>';
echo'<option value="6">6</option>';
echo'<option value="7">7</option>';
echo'<option value="8">8</option>';
echo'<option value="9">9</option>';
echo'<option value="10">10</option>';
echo'<option value="11">11</option>';
echo'<option value="12">12</option>';
echo'<option value="13">13</option>';
echo'<option value="14">14</option>';
echo'<option value="15">15</option>';
echo'<option value="16">16</option>';
echo'</select>';
echo'<br>';
echo'<div id="naar"> </div>';
?>
$sql = "SELECT * FROM unitmembers WHERE unitid = 10";
$res = mysql_query($sql) or die (mysql_error());
while($list = mysql_fetch_object($res)) {
<script language="javascript">
function addDropDown(aantal) {
document.getElementById('naar').innerHTML = '';
for (i = 1; i <= aantal; i++ ) {
document.getElementById('naar').innerHTML += 'Player:<select name="text"><option value="$list->userid">$list->userid</option></select><br><br>';
}
}
</script>
}
echo'<select name="van" onChange="addDropDown(this.value);">';
echo'<option>- Losing Players -</option>';
echo'<option value="2">2</option>';
echo'<option value="3">3</option>';
echo'<option value="4">4</option>';
echo'<option value="5">5</option>';
echo'<option value="6">6</option>';
echo'<option value="7">7</option>';
echo'<option value="8">8</option>';
echo'<option value="9">9</option>';
echo'<option value="10">10</option>';
echo'<option value="11">11</option>';
echo'<option value="12">12</option>';
echo'<option value="13">13</option>';
echo'<option value="14">14</option>';
echo'<option value="15">15</option>';
echo'<option value="16">16</option>';
echo'</select>';
echo'<br>';
echo'<div id="naar"> </div>';
?>
Gewijzigd op 01/01/1970 01:00:00 door Robin Peters
PHPerik:
Ehh, je gebruikt PHP en Javascript zomaar door elkaar terwijl dat niet mag?
Ok, maar weet iemand dan meschien een manier hoe ik die variable uit mijn mysql db kan halen via java?
java != javascript
Je stelt nu dus eigenlijk 3 vragen door elkaar...